[chirp_devel] help interpreting a hexdump

[Rhett Robinson]

What was the question to which that was the vendor's response? I don't
really know how to interpret that without a bit more context, sorry. Saying
B3 refers to the third bit is plausible.

On Wed, Jan 24, 2018 at 12:44 PM, Rob Owens via chirp_devel <
chirp_devel at intrepid.danplanet.com> wrote:

> Thanks.  So here's a follow-up question.  Here is the vendor's response,
> verbatim:  "0x0187，B3：Wirelsee start,B2:function enable".  Do you suppose
> the B3 and B2 refer to the third and second bits within the 0x0187 byte?
> Is that typical notation?
>
> On Wed, Jan 24, 2018 at 2:34 PM, Rhett Robinson <rrhett at gmail.com> wrote:
>
>> Yes, hexdump prints each line as 16 bytes: two blocks of 8 bytes each,
>> beginning with the address of the first byte. So, in your example:
>> 00000180  63 ff ff ff 32 ff ec f3  f2 87 44 03 14 23 01 01
>> |c...2.....D..#..|
>>
>> The first byte, 63 is at 0x180. The second byte, ff is at 0x181. The 7th
>> byte, at address 0x187, is f3. After that it is f2 at 0x188, 87 at 0x189,
>> 44 at 0x18a through 01 at 0x18f. So each block will be 0x???0 through
>> 0x???f.
>>
>> Hope that helps!
>>
>> Rhett
>>
>> On Wed, Jan 24, 2018 at 11:13 AM, Rob Owens via chirp_devel <
>> chirp_devel at intrepid.danplanet.com> wrote:
>>
>>> Here are two consecutive lines from a 'hexdump -C' of a Chirp image:
>>>
>>> 00000180  63 ff ff ff 32 ff ec f3  f2 87 44 03 14 23 01 01
>>> |c...2.....D..#..|
>>> 00000190  0f 37 1d 65 05 f0 fc d3  00 0a 0a 00 3c 00 e3 3c
>>> |.7.e........<..<|
>>>
>>> Based on information from the radio vendor (Leixen), I am interested in
>>> memory address 0x0187.
>>> Is that the "f3" byte?
>>>
>>> I understand the concept of different base numbering systems, but I'm
>>> rusty.  And I'm brand new to this Chirp driver stuff...
>>>
>>> -Rob
>>>
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>>> jects/chirp/wiki/Developers
>>>
>>
>>
>
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